Reverse Number in Python

Introduction to Reverse Number in Python

In Python, a reverse operation is described as switching the front-to-back or back-to-front order of the input supplied to a variable. Python’s conditional statements (while, if, and for loops) may be used in any number of logical configurations to do this task. Python’s conditional statements may be used in conjunction with the language’s list method, slice method, recursion technique, etc. to create a logical function that operates in reverse. The Reverse() function provides a simple means of doing this for any given input.

user.

Logic for Reverse Number in Python

The following are some quick reminders on how to flip a given integer in Python:

• The input number can be read by using input () or raw_input () method.
• Next, check whether the entered value is an integer or not.
• Now check whether a given integer is greater than 0 or not.
• Create a variable called reverse and initialize the variable value with 0.
• Now find the remainder for the given input number by using the mod (%) operator.
• Multiply the variable reverse with 10 and add the remainder value to it.
• Now floor (floor division is performing the division operation and resulting value provides lower integer to the value) divide the given input number with 10.
• The given input number will become 0 at some point.
• Now repeat the steps 5, 6, 7 until you get the input number is not greater than zero.
• In the last step, display the variable in reverse.

Reversing the Number Using different ways in Python

These are some of the several approaches:

Python:

Identifier:

1. Using Slicing Method

def reverse_slicing(s):
return s[::-1]
my_number = '123456'
if __name__ == "__main__":
print('Reversing the given number using slicing =', reverse_slicing(my_number)) Steps for Implementation:

Resulting

• Save the python code in your drive. (Here, we have used D drive for executing the programs)
• Now open the command prompt and locate your drive.
• Execute the program with the command as python program_name.py
• The python programs will be saved with .py extension.

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Note: Use the aforementioned procedures as a basis for running the reverse python scripts we’ll be discussing next.

Code:

2. Using For loop Method

Resulting def reverse_for_loop(s):
s1 = ''
for c in s:
s1 = c + s1
return s1
my_number = '123456'
if __name__ == "__main__":
print('Reversing the given number using for loop =', reverse_for_loop(my_number)):

Code:

3. While Loop Method

Production Code: def reverse_while_loop(s):
s1 = ''
length = len(s) - 1
while length >= 0:
s1 = s1 + s[length]
length = length - 1
return s1
my_number = '123456'
if __name__ == "__main__":
print('Reversing the given number using while loop =', reverse_while_loop(my_number))


Code:

4. Using Reversed Method

Resulting def reverse(string):
= "123456"
print ("The given number is : ",end="")
print (my_number)
print ("Reversing the given number using reversed is : ",end="")
print (reverse(my_number))

Indicator

5. Using user-entered number and then reversing it

:

Resulting My_Number = int(input("Please provide the number to be reversed: "))
Reverse_Number = 0
while(My_Number > 0):
Reminder = My_Number %10
Reverse_Number = (Reverse_Number *10) + Reminder
My_Number = My_Number //10
print("Reverse of the provided number is = %d" %Reverse_Number):

Indicator

6. Two-Digit Reverse Method

:

Input: My_Number = int(input("Please provide the number to be reversed: "))
Reverse_Number = 0
temp = Reverse_Number
Reminder = 1
for i in range (Reminder+1):
Reminder = My_Number %10
Reverse_Number = (Reverse_Number *10) + Reminder
My_Number = My_Number //10
print("Reverse of the provided number is = %d" %Reverse_Number) Result:

Code:

7. Three-Digit Reverse Method

Final Product: My_Number = int(input("Please provide the number to be reversed: "))
Reverse_Number = 0
temp = Reverse_Number
Reminder = 1
for i in range (Reminder+2):
Reminder = My_Number %10
Reverse_Number = (Reverse_Number *10) + Reminder
My_Number = My_Number //10
print("Reverse of the provided number is = %d" %Reverse_Number)

The W01A8@@7 error code indicates:

Final Product: my_num=str(input("Enter the number to be reversed: "))
print("Reverse of the given number is: ")
print(my_num[::-1])

Number-Code

9. With Recursion Method

def reverse(s):
operator">+ s[0]
my_number = "123456789"
print ("The given number is : ",end="")
print (my_number)
print ("Reversing the given number using recursion is : ",end="")
print (reverse(my_number)) Resulting Output

0

Code:

10. Using Function Method

Product of def rev_number(My_Number) :
reverse_num = 0
while(My_Number) :
Reminder = My_Number % 10
reverse_num = reverse_num* 10 + Reminder
My_Number //= 10
return reverse_num
if __name__ == "__main__" :
My_Number = int(input('Please provide the number to be reversed:: '))
print('Reverse of the provided number is: ', rev_number(My_Number))

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Code:

11. Using List Method

Resulting number = "123456789"
print ("The given number is : " + number)
#converting number into list
list1 = list(number)
#applying reverse method of list
list1.reverse()
#converting list into number
number = ''.join(list1)
print ("Reverse of the provided number is : " + number)

2

Code:

12. Using the Stack Method

Resulting def create_stack():
#creating a list as stack and return it
stack = []
return stack
def push(stack,element):
#adding new element to list
stack.append(element)
def pop(stack):
#deleting the last element from the list
if len(stack) == 0:
return
return stack.pop()
def reverse(number):
#reversing the number by using stack's functions
num = len(number)
#creating empty list (stack)
stack = create_stack()
#inserting number into list
for i in range(0,num):
push(stack,number[i])
number = ""
#getting last element of the stack list
for i in range(0,num):
number = number + pop(stack)
return number
number1 = "123456789"
number2 = reverse(number1)
print ("The given number is : " + number1)
print ("Reverse of the given number is : " + number2)

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